63q^2+70=77

Solution for 63q^2+70=77 equation:

63q^2+70=77

We move all terms to the left:

63q^2+70-(77)=0

We add all the numbers together, and all the variables

63q^2-7=0

a = 63; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·63·(-7)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42}{2*63}=\frac{-42}{126}
=-1/3
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42}{2*63}=\frac{42}{126}
=1/3
$